wrapt.decorator does not work with super about wrapt HOT 4 CLOSED

Sorry should have mentioned that this is code run under python 2.7

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The quick answer is that you need to use:

super(Class2.__wrapped__, self).__init__()

I haven't looked closely at how super() works yet, but my expectation is that it only uses the result of type() and so there is not going to be a way of fooling it in a way so as to avoid needing to do this.

The wrapper in this case at least provides wrapped to allow you access to the original wrapped class, which would not necessarily be possible if traditional ways of using a function closure had been used, especially in Python 2.

In Python 3.X, the functools.wraps() does introduce the notion of wrapped so technically if people at least used functools.wraps() with a function closure based decorator then this will also work for Python 3 if not using wrapt decorators.

Either way, if decorating a class and the decorator function isn't just annotating the class and returning it, you need to use a mechanism like this to grab a reference to the original wrapped class in order to satisfy super().

I would imagine that if using Python 3, you can probably get away with using the new super() feature which avoids you needing to pass in the class type and self.

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Thanks for the explanation Graham. It's appreciated. I'm going to switch back to old style Class1.__init__(self) for now as this library is too cool to pass up. Could this be documented in the known issues section?

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Documentation added about this issue for version 1.7.0.

Interesting to note is that the new magic super() in Python 3 was in part driven by this issue with decorated classes and needing access to the original type. This is noted in following commentary.

• http://stackoverflow.com/a/19609168/128141

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