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Supowit's algorithm.
Line 33 in 9298690
While the matched point k corresponding to the end point j is between j and start point i, the equation would be
MIS(i, j) = max(MIS(i, j-1), MIS(i, k-1) + 1 + MIS(k+1, j-1))
However, MIS(k+1, j-1)
will become to MIS(j, j-1)
when k = j-1
.
And it breaks the rule for the function MIS(a, b)
that b
must be larger than a
.
Moreover, it may lead to overflow if it keeps going on matching the equation MIS(i, j) = MIS(i, j-1)
.
Don't simplify MIS(i, k-1) + MIS(k, j)
into MIS(i, k-1) + 1 + MIS(k+1, j-1)
and the problem(k = j-1) will be handled well while it goes recursion.
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