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from ffmpegwrapper import FFmpeg, Input, Output
When running FFmpeg('ffmpeg', Input('a.mp4'), Output('-b.mp4')), ffmpeg gives "Unrecognized option 'b.mp4'."
It seems that the command becomes ffmpeg -i a.mp4 -b.mp4
But the command should be ffmpeg -i a.mp4 -- -b.mp4 to prevent the issue (by adding --).

Hi,

I am trying to convert quite a lot of m4a files into mp3 files with the following piece of code:

for root,dirs,files in os.walk("/Users/jonathan/Desktop/Music1"): 
    for file1 in files:
        if file1[len(file1)-3:len(file1)] == "m4a":
            input1 = Input("/Users/jonathan/Desktop/Music1/"+file1)
            codec = AudioCodec("libmp3lame")
            output = Output("/Users/jonathan/Desktop/MP3/"+file1[0:len(file1)-3]+"mp3", codec) #replace the path
            ffmpeg = FFmpeg("ffmpeg", input1, output)
            ffmpeg.run()

It works fine until a certain point, when it crashes and shows the following message:
Traceback (most recent call last): File "antomp3.py", line 18, in <module> ffmpeg.run() File "/Users/jonathan/anaconda/lib/python2.7/site-packages/ffmpegwrapper-0.1_dev-py2.7.egg/ffmpegwrapper/ffmpeg.py", line 158, in run return FFmpegProcess(self).run() File "/Users/jonathan/anaconda/lib/python2.7/site-packages/ffmpegwrapper-0.1_dev-py2.7.egg/ffmpegwrapper/ffmpeg.py", line 97, in run stdin=PIPE, stdout=PIPE, stderr=STDOUT) File "/Users/jonathan/anaconda/lib/python2.7/subprocess.py", line 711, in __init__ errread, errwrite) File "/Users/jonathan/anaconda/lib/python2.7/subprocess.py", line 1197, in _execute_child errpipe_read, errpipe_write = self.pipe_cloexec() File "/Users/jonathan/anaconda/lib/python2.7/subprocess.py", line 1153, in pipe_cloexec r, w = os.pipe() OSError: [Errno 24] Too many open files

I've been reading about this error message on the web and it seems that it is a problem of not closing the files opened through Popen(). Can you help me fix this?