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Home Page: https://docs.rs/strong_id
License: Apache License 2.0
Strongly typed IDs
Home Page: https://docs.rs/strong_id
License: Apache License 2.0
I wanted to add a StrongId in a codebase that already has a declaration like,
pub type Result<T> = std::result::Result<T, OurError>;
This is a pattern I've seen in a few rust projects.
That definition makes my use of strong_id::strong_id!()
fail - the macro output expects but does not explicitly specify std::result::Result
rather than this type alias.
One workaround is to wrap the strongid definition in a submodule and pub-use the result:
mod myid {
use strong_id::strong_uuid;
use std::result::Result;
strong_uuid!(pub struct RequestId(Uuid => "req"));
}
pub use myid::RequestId;
Consider explicitly qualifying ::std::result::Result
within macro-generated code.
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