johnnynotsolucky / strong_id Goto Github PK

I wanted to add a StrongId in a codebase that already has a declaration like,

pub type Result<T> = std::result::Result<T, OurError>;

This is a pattern I've seen in a few rust projects.

That definition makes my use of strong_id::strong_id!() fail - the macro output expects but does not explicitly specify std::result::Result rather than this type alias.

One workaround is to wrap the strongid definition in a submodule and pub-use the result:

mod myid {
    use strong_id::strong_uuid;
    use std::result::Result;
    strong_uuid!(pub struct RequestId(Uuid => "req"));
}
pub use myid::RequestId;

Consider explicitly qualifying ::std::result::Result within macro-generated code.