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JoshTheDerf avatar JoshTheDerf commented on July 1, 2024

@le717 Since the parts are referred to by name, the only check needed is to see if the part is not already cached. If it is, then nothing needs to change since the partId is already referenced by name.

But yeah, the cache works fine. :)

I'll comment better next time, I prawmise. :3

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le717 avatar le717 commented on July 1, 2024

I'm not sure where then parts are being retrieved from the cache, but since it works, my question has been answered and this can be closed. :)

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JoshTheDerf avatar JoshTheDerf commented on July 1, 2024

@le717 The idea is that parts never have to be "retrieved" until parsing the output. It might make sense if you take a closer look at the output format.

All the parser has to know is that a part is cached.

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