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operating-systems-three-easy-pieces-notes's Introduction

如果你想写一个简单的操作系统,可以参考我的项目 quarkOS,我会慢慢补充一些开发资料 😂

仓库并非标准答案,只是作者在阅读操作系统导论时的解答,以及对部分 README 的翻译

本人翻译水平有限,见谅。欢迎指出错误

部分章节课后习题在中文翻译书上是没有的,但在原版上存在 :

英文原版: http://pages.cs.wisc.edu/~remzi/OSTEP/

书籍翻译: https://github.com/remzi-arpacidusseau/ostep-translations

代码无法运行

本书代码测试环境为 Intel x64/Ubuntu

gcc 版本为:gcc version 9.3.0 (Ubuntu 9.3.0-17ubuntu1~20.04)

Python2 版本:Python 2.7.18

Python3 版本: Python 3.8.5

第三方 Python3 库: pip3 install matplotlib numpy

遇到无法运行的代码请检查是否为版本问题

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operating-systems-three-easy-pieces-notes's Issues

运行报错

Windows 下运行第四章代码报错,请问如何解决,python 版本 3.8.3
image

05.第五章-插叙:进程API 课后习题第二题

用fork()创建一个新进程。当它们并发(即同时)写入文件时,会发生什么?

这个父子进程是可以对同一个文件描述符写入的好吧,写肯定是会写入的,但父子进程写入顺序不一定

16章的第三题练习题答案有问题

--b1应该是16
运行结果
python2 segmentation.py -a 16 -p 128 -A 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15 --b0 0 --l0 2 --b1 16 --l1 2 -c
ARG seed 0
ARG address space size 16
ARG phys mem size 128

Segment register information:

Segment 0 base (grows positive) : 0x00000000 (decimal 0)
Segment 0 limit : 2

Segment 1 base (grows negative) : 0x00000010 (decimal 16)
Segment 1 limit : 2

Virtual Address Trace
VA 0: 0x00000000 (decimal: 0) --> VALID in SEG0: 0x00000000 (decimal: 0)
VA 1: 0x00000001 (decimal: 1) --> VALID in SEG0: 0x00000001 (decimal: 1)
VA 2: 0x00000002 (decimal: 2) --> SEGMENTATION VIOLATION (SEG0)
VA 3: 0x00000003 (decimal: 3) --> SEGMENTATION VIOLATION (SEG0)
VA 4: 0x00000004 (decimal: 4) --> SEGMENTATION VIOLATION (SEG0)
VA 5: 0x00000005 (decimal: 5) --> SEGMENTATION VIOLATION (SEG0)
VA 6: 0x00000006 (decimal: 6) --> SEGMENTATION VIOLATION (SEG0)
VA 7: 0x00000007 (decimal: 7) --> SEGMENTATION VIOLATION (SEG0)
VA 8: 0x00000008 (decimal: 8) --> SEGMENTATION VIOLATION (SEG1)
VA 9: 0x00000009 (decimal: 9) --> SEGMENTATION VIOLATION (SEG1)
VA 10: 0x0000000a (decimal: 10) --> SEGMENTATION VIOLATION (SEG1)
VA 11: 0x0000000b (decimal: 11) --> SEGMENTATION VIOLATION (SEG1)
VA 12: 0x0000000c (decimal: 12) --> SEGMENTATION VIOLATION (SEG1)
VA 13: 0x0000000d (decimal: 13) --> SEGMENTATION VIOLATION (SEG1)
VA 14: 0x0000000e (decimal: 14) --> VALID in SEG1: 0x0000000e (decimal: 14)
VA 15: 0x0000000f (decimal: 15) --> VALID in SEG1: 0x0000000f (decimal: 15)

15章的练习题2,3,4有问题

15章的的第2个练习题,最大的虚拟地址为929要想使地址范围[0,929]完全处于边检内需要设置界限为930也就是一个930大小的地址空间,第3题和第4题同理

题目

十四章第一题,你没有释放内存吧?
原题:首先,编写一个名为 null.c 的简单程序,它创建一个指向整数的指针,将其设置为 NULL,然后尝试对其进行_释放内存_操作。把它编译成一个名为 null 的可执行文件

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