looomenn / replace_power Goto Github PK

used match ( PEP 636 )

To run script you need python >=3.10

You can run the script from the command-line using

python _power.py

Used math formula

 a ≅ b (mod m)

Find the remainder from dividing:

$$2^{100} + 5^{200} : 29 \ (ex.)$$

As a result, we must convert the power of $\boldsymbol{100}$ and $\boldsymbol{200}$ to some normal numbers. According to the theory of division with remainder we need power of 2 (from ex.) when it is equal to 1 or -1, so we can replace it.

Additionaly, $\boldsymbol{A}$ is a firstly given number (base number), $\boldsymbol{P}$ is number that we want ( power of base number ) and $\boldsymbol{M}$ - modulus.

The first line of the input gives state of program output:

 0 - Limit On | 1 - Limit off | 2 - Debug + Limit on | 3 - Debug only

The second line gives the number of test cases, $\boldsymbol{T}$. $\boldsymbol{T}$ test cases follow. Each test case has a single line containing three integers, $\boldsymbol{A}$, $\boldsymbol{P}$ and $\boldsymbol{M}$, as described above.

In program A = given_int; P = power; M = modulus

With this parameter, we can specify whether the program should stop at -1 / 1 or continue with the given power.

For each test case, output the first line containing Case #x: y, where x is the test case number (starting from 1) and y is a list that contains dictionary with possible replacable equations.

Output format

<give_int>^<power> ≅ <result_number> (mod M)

2
1
7 10 100

2 - state 2 $\implies$ Debug + Limit 1 - number of test cases 7 - given $\boldsymbol{A}$ 10 - given $\boldsymbol{P}$ 100 - given $\boldsymbol{M}$

[DEBUG] operation: -     power: 3     old: 343   new: 243
[DEBUG] operation: -     power: 3     old: 243   new: 143
[DEBUG] operation: -     power: 3     old: 143   new: 43
[DEBUG] operation: -     power: 4     old: 301   new: 201
[DEBUG] operation: -     power: 4     old: 201   new: 101
[DEBUG] operation: -     power: 4     old: 101   new: 1
Case #1: [{'7^1 ≅ 7 (mod 100)'}, {'7^2 ≅ 49 (mod 100)'}, {'7^3 ≅ 43 (mod 100)'}, {'7^4 ≅ 1 (mod 100)'}]