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Could you point to a place where you would show how this program could be modified to record from one (speaker) device and then playback to another ?

I am trying to do this with a device where the mixer device is not present.

Hi,
Hope your are enjoying good health?
I want to use loop back software with ffmpeg string. Can you help me doing this or some sorts solution. So, I can use it with ffmpeg string directly.
Hope you understand my question.
Thanks for your help.

The variable bInt16 always will be false at loopback-capture.cpp making of what's inside the statement useless.

You do this:

if (bFirstPacket && AUDCLNT_BUFFERFLAGS_DATA_DISCONTINUITY == dwFlags) {
            LOG(L"%s", L"Probably spurious glitch reported on first packet");
        } else if (0 != dwFlags) {
            LOG(L"IAudioCaptureClient::GetBuffer set flags to 0x%08x on pass %u after %u frames", dwFlags, nPasses, *pnFrames);
            return E_UNEXPECTED;
        }

On my PC I systematically receive a combination of AUDCLNT_BUFFERFLAGS_DATA_DISCONTINUITY and AUDCLNT_BUFFERFLAGS_SILENT on the 1st packet so the code will return E_UNEXPECTED and I don't see why it should.

I think you should just test for AUDCLNT_BUFFERFLAGS_TIMESTAMP_ERROR (maybe? can't we just continue even on this error?) and don't care about the other flags? At least it works for me with these changes.

PS: There's another glitch with the keyboard test: if I run the app from a console, it exits immediately. I had to change the stdin test events.

Just a small issue. The function CreateFile() returns in case of error INVALID_HANDLE_VALUE and not NULL or nullptr.
Thank you for the code.

Hi, I am reading your article : Hacking private keys from unsafe primes using the Pohlig-Hellman discrete logarithm. I found that the final solution for 6^a = 2 % p does not seem to use the small subgroup. Just like 100000008359680 = 2^8 5 11^2 13 19 31 37 43 53. Instead, solve the DLP problem directly in the large group p = 100000008359681. I am confused about this, please help me understand, thanks