rpcx microservice framework in Rust
Home Page: https://rpcx.io
License: Apache License 2.0
大道至简，简即是繁
rpcx_client 工程 -> src -> client.rs -> 93行
if self.opt.write_timeout.as_millis() > 0 {
stream.set_write_timeout(Some(self.opt.read_timeout))?;
}
这个写错了，将read_timeout设置到 write上
这样很不方便复用，不过我rust 不太熟悉。我理解的对吗
有计划支持async/await吗？
tokio升级到0.2？或者是支持smol或async-std？
我想注册
register_func!(
rpc_server,
RPC_PS_Path,
RPC_PS_Write,
write,
"".to_owned(),
WriteRequest,
WriteResponse
);
如果方法绑定在对象上 如
struct AAA{
}
impl AAA{
pub fn write(req) -> rep {}
}
register_func!(
rpc_server,
RPC_PS_Path,
RPC_PS_Write,
AAA.write,
"".to_owned(),
WriteRequest,
WriteResponse
);
不行的。
然后我用闭包
let write = |x: WriteRequest| -> WriteResponse {
let rep: WriteResponse = Default::default();
rep
};
register_func!(
rpc_server,
RPC_PS_Path,
RPC_PS_Write,
write,
"".to_owned(),
WriteRequest,
WriteResponse
);
还是不工作，这个问题该如何处理呀？谢谢
根据 Server::start 的函数签名：
pub fn start(&mut self) -> Result<()>可以看到这里使用的是可变借用。该函数一旦执行将一直阻塞，直到 listen 用 fd 被关闭。
而这个 fd 只会在 Server::close 函数中被关闭，以下是它的函数签名：
pub fn close(&self)可以看到这里有一个不可变借用。
由于 Rust 语言限制同一个变量的可变借用和不可变借用不能同时存在，因此在调用 start 函数之后，无法再调用 close 函数将其关闭。
请问有无优雅的方式来将正在监听的 RPC Server 关闭？
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