[email protected]:Ty-Nickel/Python.git
import fcntl, termios, struct, os import random import time, sys
def ioctl_GWINSZ(fd): ''' Get terminal size, by giving the proper file descriptor ''' try: cr = struct.unpack('hh', fcntl.ioctl(fd, termios.TIOCGWINSZ, '1234')) except: return None return cr
def get_terminal_size(): ''' Get terminal size, or assume one '''
# Either stdin (0), stdout (1), stderr (2)
cr = ioctl_GWINSZ(0) or ioctl_GWINSZ(1) or ioctl_GWINSZ(2)
# If not available in either of these
# obtain the proper file descriptor
if not cr:
try:
fd = os.open(os.ctermid(), os.O_RDONLY)
cr = ioctl_GWINSZ(fd)
os.close(fd)
except:
pass
# If still not available
# get the information from the environment, or assume a size
if not cr:
try:
cr = (env['LINES'], env['COLUMNS'])
except:
cr = (25, 80)
return int(cr[1]), int(cr[0])
def get_rand_num(): ''' Get 0, 1, or 2 randomly for the matrix ''' return random.randint(0, 2)
def get_line(): ''' Return a line with numbers that is as long as the width of the current terminal ''' n = 0 line = ''
width, height = get_terminal_size()
while n < width:
width, height = get_terminal_size()
line += str(get_rand_num())
n += 1
return line
def matrix(): ''' Create a pseudo-matrix of binary numbers scrolling in one horizontal line. It is inspired in how the code looks like in the movie The Matrix ''' n = 0 t = 0.50 # Seconds after which the line refreshes
width, height = get_terminal_size()
# Refresh the line until a keyboard interrupt
while n < height:
try:
# Only '0' and '1', with random spaces in between
binary_line = get_line().replace('2', ' ')
# Write to the terminal,
# returning the cursor to the beginning of the line
sys.stdout.write('\033[1m\033[32m' + binary_line + '\033[0m' + '\r')
sys.stdout.flush()
time.sleep(t)
except KeyboardInterrupt, EOFError:
# Ctrl+C, Ctrl+D
sys.stdout.write('\n' + '=== END ===' + '\n')
sys.stdout.flush()
time.sleep(1.0)
break
matrix()
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