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genetics-problems

Python Scripts for Generating Genetics Homework/Quiz problems

Table of Contents

Created by gh-md-toc

Blood Types

blood_type_agglutination_test.py

What will the results of a blood test look like for a person with O- blood type?

  • A. Image Choice 1
  • B. Image Choice 2

blood_type_offspring.py

  1. For the ABO blood group in humans, the iA and iB alleles are codominant and the i allele is recessive. If a female ♀ with type A blood marries a male ♂ with type O blood, which of the following blood types could their children possibly have? Check all that apply.
  • A. Type O blood
  • B. Type A blood
  • C. Type B blood
  • D. Type AB blood

blood_type_mother.py

  1. For the ABO blood group in humans, the iA and iB alleles are codominant and the i allele is recessive. A father ♂ who has blood type AB has a son ♂ who has blood type A, which of the following blood types could the mother ♀ possibly have? Check all that apply.
  • A. Type O blood
  • B. Type A blood
  • C. Type B blood
  • D. Type AB blood
  • E. None of the above are possible

hla_genotype.py

  1. A mother has a HLA genotype of A2,B5,C6 on one chromosome and A1,B1,C3 on the other. The father has a HLA genotype of A7,B9,C2 on one chromosome and A8,B3,C5 on the other. Which one of the following is a possible genotype for one of their offspring?
  • A. A2,A8,B1,B9,C2,C3
  • B. A1,A2,B1,B5,C3,C6
  • C. A2,A7,B5,B9,C2,C6
  • D. A7,A8,B3,B9,C2,C5
  • E. A1,A7,B1,B3,C5,C6

Gametes

gametes_unique.py

  1. How many unique gametes could be produced through independent assortment by an individual with the genotype AA Bb cc dd Ee Ff Gg ?
  • A. 22 = 4
  • B. 23 = 8
  • C. 24 = 16
  • D. 25 = 32
  • E. 26 = 64

Epistasis

epistasis_test_cross.py

  1. In a specific cross, F2 progeny exhibit a modified dihybrid ratio of 15:1 (instead of 9:3:3:1 ). What phenotypic ratio would be expected from a test-cross with an individual from the F1 progeny?
  • A. 1:4
  • B. 2:2 or 1:1
  • C. 4:1
  • D. 3:1
  • E. 2:1
  • F. 1:3

epistasis_inverse_test_cross.py

  1. An F1 heterozygote individual from dihybrid cross is used for a test-cross. The progeny from the test-cross exhibited a modified ratio of 3:1 (instead of 1:1:1:1). What phenotypic ratio would be expected in the F2 progeny if the dihybrid cross is continued?
  • A. 13:3
  • B. 12:4
  • C. 11:5
  • D. 10:6
  • E. 9:7

X-linked disorders

poisson_flies.py

1. The white-eyed phenotype is an X-linked recessive disorder in fruit flies. The red allele, +, is dominant to the white allele, w. The offspring of size 400 from the mating of a single female and a single male are shown in the table below:

phenotypefemale ♀male ♂
red-eyed (wildtype)00
white-eyed (mutant)185215

What are the genotypes of the parents in this cross?

  • A. homozygous wildtype female (++) and male of unknown genotype
  • B. heterozygous female (+w) and wildtype male (+–)
  • C. heterozygous female (+w) and mutant male (w–)
  • D. homozygous mutant female (ww) and wildtype male (+–)
  • E. homozygous mutant female (ww) and mutant male (w–)

Chi-Squared Analysis

Table of Chi-Squared (χ2) Critical Values

Table of Chi-Squared (χ2) Critical Values
Degrees of FreedomProbability
0.950.900.750.500.250.100.050.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

chi_square_errors.py

1. The final result gives the chi-squared (χ2) test value of 3.58 with 3 degrees of freedom. Using the Table of χ2 Critical Values and a level of significance α=0.50, we get a critical value of 2.37. Since the chi-squared (χ2) test value of 3.58 is greater than the critical value of 2.37, the null hypothesis was rejected.

PhenotypeExpectedObservedCalculationStatistic
Yellow Round (Y–R–) 90 94 (94-90)2⁄ 90 0.178
Yellow Wrinkled (Y–rr) 30 21 (21-30)2⁄ 30 2.700
Green Round (yyR–) 30 33 (33-30)2⁄ 30 0.300
Green Wrinkled (yyrr) 10 12 (12-10)2⁄ 10 0.400
(sum) χ2 =  3.578


Your lab partner has done a chi-squared (χ2) test for your lab data (above), for the F2 generation in a standard dihybid cross. They wanted to know if the results confirm the expected phenotype ratios, but as usual they did something wrong. Where did they do wrong?

  • A. the expected progeny for the null hypothesis is incorrect
  • B. the degrees of freedom is wrong
  • C. the numbers in the calculation have to be squared
  • D. the wrong numbers in the calculation were used for division
  • E. the wrong rejection criteria was used

Progeny

probabiliy_of_progeny.py

A women has nine (9) children, what is the probability that she has exactly five (5) boys and four (4) girls?

Image of Probabiliy of Progeny problem

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