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fyoung-keygen's Introduction

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intro:
  netizen: 2003-now
  degree: bsc in computer science, sichuan university
  coding: naively
  current: freelance developer

code:
  frontend: {css, js, ts, vue, react, ...}
  backend: {php, python, node, go}
  native: {c, cpp, csharp, ...}
  operation: {linux, nginx}
  security: do i really know this?

interests:
  - user experience
  - data science
  - ...

mailto: [email protected]

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fyoung-keygen's Issues

关于主代码的一些修正

19-20秋季学期飞扬俱乐部招新的时候博主给了我这个代码,说是win10这里不太适合。让我自己去看看。当时c++很渣,渣到这些代码都看不懂。后来就搁置了。
现在放假我又回来看了看,调试再加修改,终于发现了这个代码的一些问题,然后进行了一些些修改,并成功拨号。
下面是我的一些修改意见。

我作的修改主要都是主程序中的修改。

1. fyoung.c的47:

if (argc<3) return 0;

因为我的c++并不好,这里我运行的时候总是到这里就直接退出,不进行下面的代码.然后我将if的执行块加了花括号,就可以正常运行了.

if (argc<3) {return 0;}

2. fyoung.c的48:

if (strstr(argv[1], "tyfy") == NULL){
        printf("%s", argv[1]);
    } 

这里我不知道为什么要判定账号里是否含"tyfy",可能老版本的账号里有?也不知道为什么不含"tyfy"的话就直接返回原账号.这里我把判定条件修改为不为空,以进行下面的步骤.

if (strstr(argv[1], "tyfy") != NULL){
        printf("%s", argv[1]);
    } 

3. fyoung.c的54:

CalcRealID(argv[1]+4,argv[2],timestamp,userID);

这里我也不清楚为什么要把账号加4.因为我从系统事件查看器中找到的真实拨号账号是直接含原始账号的,所以我尝试着把这个"+4"去掉

CalcRealID(argv[1],argv[2],timestamp,userID);

最后发现这样修改后得出的账号是可以成功拨号的,所以我在此提出我的实践看法.

希望博主给出意见,毕竟我只是个新手菜鸟.
现在由于没有可以进行烧录的开源路由器,目前还没有进行下一步对路由器的操作.但还在摸索,希望可以以后和博主进行交流学习.

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