Let's make a fucking leedcode team~
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@曹老师，LCA的问题
1、这个是搜索二叉树还是普通二叉树
2、为啥没有条件判断呀
3、如果节点1在root左子树上，节点2在root右子树上，貌似代码判断不出来呀，代码AC了么？
原理是不是这个？
1 如果两个节点都比当前节点小, 那公共祖先必然是当前节点的左子树上, 所以递归左子树;
2 如果两个节点都比当前节点大, 那么同上, 递归右子树;
3 如果两个节点有一个为当前节点, 则当前节点为公共节点; 如果两个节点分别比当前节点小和大, 那么当前节点必为公共节点.
下次提交题目的时候，最好也写上OJ地址
牛客网的也行不？
为什么首位是0的ip不合理
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