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callqh avatar callqh commented on June 15, 2024

题解

#39 思路一致。就是要注意些细节问题。
这里因为是指定val值,所以可能第一个元素就是val,这里就要在原地将该值修改掉,所以要先修改slow的值,然后然slow走到下一个元素的位置等待是否修改。
这样的话就导致,最后每次修改slow位置值之后他都是在下一位等待的,也就是slow就是最后数组的长度 len = last_index+1

/**
 * @param {number[]} nums
 * @param {number} val
 * @return {number}
 */
var removeElement = function(nums, val) {
    let fast = slow = 0;
    while(fast<nums.length){
        if(nums[fast] !== val){
            nums[slow] = nums[fast];
            slow++;
        }
        fast++
    }
    return slow
};

from algorithm.

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