Comments (1)
const twoSum = (nums: number[], target: number) => {
let result: number[] = [];
let map: Map<number, number> = new Map();
for (let i = 0; i < nums.length; i++) {
let temp = target - nums[i];
let index = map.get(temp);
if (index !== undefined) {
result.push(index, i);
break;
}
map.set(nums[i], i);
}
return result;
};
console.log(twoSum([2, 11, 15, 7], 9));
console.log(twoSum([20, 55, 34, 69, 81, 92, 18], 38));
console.log(twoSum([3, 2, 4], 6));
console.log(twoSum([3, 3], 6));
from leetcode.
Related Issues (11)
- 2 - 两数相加 HOT 2
- 3 - 无重复字符的最长子串 HOT 1
- 4 - 寻找两个正序数组的中位数 HOT 2
- 5 - 最长回文子串 HOT 2
- 10 - 正则表达式匹配 HOT 1
- 11 - 盛最多水的容器 HOT 1
- 15 - 三数之和 HOT 1
- 17 - 电话号码的字母组合 HOT 1
- 19 - 删除链表的倒数第 N 个结点 HOT 1
- 20 - 有效的括号
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from leetcode.