Comments (1)
class ListNode {
val: number;
next: ListNode | null;
constructor(val?: number, next?: ListNode | null) {
this.val = val === undefined ? 0 : val;
this.next = next === undefined ? null : next;
}
}
function removeNthFromEnd(head: ListNode | null, n: number): ListNode | null {
let dummy: any = new ListNode(0, head);
let left = dummy;
let right = dummy;
while (n >= 0) {
right = right.next;
n--;
}
while (right) {
right = right.next;
left = left.next;
}
left.next = left.next.next;
return dummy.next;
}
const l1 = new ListNode(1);
l1.next = new ListNode(2);
l1.next.next = new ListNode(3);
l1.next.next.next = new ListNode(4);
console.log(removeNthFromEnd(l1, 3));
from leetcode.
Related Issues (11)
- 1 - 两数之和 HOT 1
- 2 - 两数相加 HOT 2
- 3 - 无重复字符的最长子串 HOT 1
- 4 - 寻找两个正序数组的中位数 HOT 2
- 5 - 最长回文子串 HOT 2
- 10 - 正则表达式匹配 HOT 1
- 11 - 盛最多水的容器 HOT 1
- 15 - 三数之和 HOT 1
- 17 - 电话号码的字母组合 HOT 1
- 20 - 有效的括号
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from leetcode.