Comments (2)
中心扩散
const longestPalindrome = function (s: string): string {
let len = s.length;
if (len === 0 || len === 1) return s;
let start = 0,
end = 0,
maxLen = 0,
minLen = 0;
const f = (s: string, start: number, end: number) => {
while (start >= 0 && end <= len - 1 && s[start] === s[end]) {
start--;
end++;
}
if (end - (start + 1) > maxLen - minLen) {
minLen = start + 1;
maxLen = end;
}
};
for (let i = 1; i < len; i++) {
f(s, i, i);
f(s, i - 1, i);
}
return s.substring(minLen, maxLen);
};
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动态规划
不会
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Related Issues (11)
- 1 - 两数之和 HOT 1
- 2 - 两数相加 HOT 2
- 3 - 无重复字符的最长子串 HOT 1
- 4 - 寻找两个正序数组的中位数 HOT 2
- 10 - 正则表达式匹配 HOT 1
- 11 - 盛最多水的容器 HOT 1
- 15 - 三数之和 HOT 1
- 17 - 电话号码的字母组合 HOT 1
- 19 - 删除链表的倒数第 N 个结点 HOT 1
- 20 - 有效的括号
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