Comments (2)
暴力解决
复杂度不对
const findMedianSortedArrays = (num1: number[], num2: number[]): number => {
const res: number[] = [];
let i = 0;
let j = 0;
while (i < num1.length && j < num2.length) {
if (num1[i] < num2[j]) {
res.push(num1[i]);
i++;
} else {
res.push(num2[j]);
j++;
}
}
while (i < num1.length) {
res.push(num1[i]);
i++;
}
while (j < num2.length) {
res.push(num2[j]);
j++;
}
const len = res.length;
if (len % 2 === 0) {
return (res[len / 2] + res[len / 2 - 1]) / 2;
} else {
return res[(len - 1) / 2];
}
};
console.log(findMedianSortedArrays([2], [3])); // 2.5
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二分查找
不会
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Related Issues (11)
- 1 - 两数之和 HOT 1
- 2 - 两数相加 HOT 2
- 3 - 无重复字符的最长子串 HOT 1
- 5 - 最长回文子串 HOT 2
- 10 - 正则表达式匹配 HOT 1
- 11 - 盛最多水的容器 HOT 1
- 15 - 三数之和 HOT 1
- 17 - 电话号码的字母组合 HOT 1
- 19 - 删除链表的倒数第 N 个结点 HOT 1
- 20 - 有效的括号
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