Comments (1)
function threeSum(nums: number[]): number[][] {
const result: number[][] = [];
const len = nums.length;
if (len < 3) return result;
nums.sort((a, b) => a - b);
for (let i = 0; i < len - 2; i++) {
if (nums[i] > 0) break;
if (i > 0 && nums[i] === nums[i - 1]) continue;
let l = i + 1;
let r = len - 1;
while (l < r) {
const sum = nums[i] + nums[l] + nums[r];
if (sum === 0) {
result.push([nums[i], nums[l], nums[r]]);
while (l < r && nums[l] === nums[l + 1]) l++;
while (l < r && nums[r] === nums[r - 1]) r--;
l++;
r--;
} else if (sum < 0) {
l++;
} else {
r--;
}
}
}
return result;
}
from leetcode.
Related Issues (11)
- 1 - 两数之和 HOT 1
- 2 - 两数相加 HOT 2
- 3 - 无重复字符的最长子串 HOT 1
- 4 - 寻找两个正序数组的中位数 HOT 2
- 5 - 最长回文子串 HOT 2
- 10 - 正则表达式匹配 HOT 1
- 11 - 盛最多水的容器 HOT 1
- 17 - 电话号码的字母组合 HOT 1
- 19 - 删除链表的倒数第 N 个结点 HOT 1
- 20 - 有效的括号
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from leetcode.